Section: Math 0 Likes

(k+2m) (3k-2m) is equivalent to: (September 2023 - G01)

Updated on 05/13/2024

(k+2m) (3k-2m) is equivalent to:

F. 3k^2 - 4m^2
G. 3k^2 + 4m^2
H. 3k^2 + 2km-4m^2
J. 3k^2 + 3km - 4m^2
K. 3k^2 + 4km - 4m^2


Solution

Correct answer: K. 3k^2 + 4km - 4m^2.
We can simplify the expression using the distributive property. The distributive property states that for any expressions A, B, and C, the following equality holds:
A(B+C) = AB+AC
Steps to solve:
1. Distribute k(3k-2m) and 2m(3k-2m):
k(3k−2m)+2m(3k−2m)
2. Distribute 3k^{2}-2km within the first set of parentheses:
3k²−2km+2m(3k−2m)
3. Distribute 6km-4m^{2} within the parentheses:
3k²−2km + 6km−4m²
4. Combine like terms:
3k² + (4k−2)m−4m²
3k² + 4km−4m²

Exam Edition: September 2023 - G01

Exam Year: 2023

Related topics: Distributive Property, Simplifying Polynomials

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