Section: Math 0 Likes
(k+2m) (3k-2m) is equivalent to: (September 2023 - G01)
(k+2m) (3k-2m) is equivalent to:
F. 3k^2 - 4m^2
G. 3k^2 + 4m^2
H. 3k^2 + 2km-4m^2
J. 3k^2 + 3km - 4m^2
K. 3k^2 + 4km - 4m^2
Solution
Correct answer: K. 3k^2 + 4km - 4m^2.
We can simplify the expression using the distributive property. The distributive property states that for any expressions A, B, and C, the following equality holds:
A(B+C) = AB+AC
Steps to solve:
1. Distribute k(3k-2m) and 2m(3k-2m):
k(3k−2m)+2m(3k−2m)
2. Distribute 3k^{2}-2km within the first set of parentheses:
3k²−2km+2m(3k−2m)
3. Distribute 6km-4m^{2} within the parentheses:
3k²−2km + 6km−4m²
4. Combine like terms:
3k² + (4k−2)m−4m²
3k² + 4km−4m²
Exam Edition: September 2023 - G01
Exam Year: 2023
Related topics: Distributive Property, Simplifying Polynomials